복붙노트

[SPRING] Spring 3.1 MVC 애플리케이션의 HTTP 상태 404

SPRING

Spring 3.1 MVC 애플리케이션의 HTTP 상태 404

내가 만들고 간단하게 봄 3.1 mvc 웹 응용 프로그램을 실행하려고합니다 아래의 클래스를 사용하여 응답 본문에 단순히 "안녕하세요"반환하는 컨트롤러를 정의한 :

package com.jr.freedom.controllers;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;

@Controller
public class Hello {

    @RequestMapping(value = "/hello", method = RequestMethod.GET)
    @ResponseBody
    public String helloWorldInJson() {

        return "hello";
    }
}

이 URL을 시도했지만 404 오류가 계속 표시됩니까?

http : // localhost : 8080 / FreedomSpring / hello

다음은 내 서블릿입니다.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans      
        http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-3.1.xsd">

    <import resource="mvc-config.xml" />

    <bean
        class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping" />

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources 
        in the /WEB-INF/views directory -->
    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/views/" />
        <property name="suffix" value=".jsp" />
    </bean>

    <bean
        class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />

    <context:component-scan base-package="com.jr.freedom.controllers"></context:component-scan>


</beans>

다음은 web.xml 파일입니다.

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
         http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <servlet>
        <servlet-name>FreedomSpring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>FreedomSpring</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>


    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>

        </param-value>
    </context-param>

    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/log4j.xml</param-value>
    </context-param>

    <welcome-file-list>
        <welcome-file>
      index.jsp
    </welcome-file>
    </welcome-file-list>

    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>

</web-app>

마지막으로 내 mvc-config.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
        http://www.springframework.org/schema/mvc 
        http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">

    <mvc:annotation-driven />

    <!-- the application context definition for the springapp DispatcherServlet -->


    <mvc:view-controller path="/" view-name="index.jsp" />


</beans>

Windows 7 컴퓨터에서 바람둥이 7을 사용하고 있습니다. tomcat의 로그 파일에서 오류를 찾을 수 없습니다.

13-Feb-2012 12:37:36 org.apache.catalina.core.ApplicationContext log
INFO: Destroying Spring FrameworkServlet 'FreedomSpring'
13-Feb-2012 12:37:36 org.apache.catalina.core.ApplicationContext log
INFO: Shutting down log4j
13-Feb-2012 12:37:36 org.apache.catalina.core.ApplicationContext log
INFO: Closing Spring root WebApplicationContext
13-Feb-2012 12:37:37 org.apache.catalina.core.ApplicationContext log
INFO: Initializing Spring root WebApplicationContext
13-Feb-2012 12:37:37 org.apache.catalina.core.ApplicationContext log
INFO: Set web app root system property: 'webapp.root' = [C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\FreedomSpring\]
13-Feb-2012 12:37:37 org.apache.catalina.core.ApplicationContext log
INFO: Initializing log4j from [C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\FreedomSpring\WEB-INF\log4j.xml]
13-Feb-2012 12:37:37 org.apache.catalina.core.ApplicationContext log
INFO: Initializing Spring FrameworkServlet 'FreedomSpring'


0:0:0:0:0:0:0:1 - - [13/Feb/2012:12:37:45 +0000] "GET /FreedomSpring HTTP/1.1" 302 -
0:0:0:0:0:0:0:1 - - [13/Feb/2012:12:37:45 +0000] "GET /FreedomSpring/ HTTP/1.1" 404 997
0:0:0:0:0:0:0:1 - - [13/Feb/2012:12:37:51 +0000] "GET /FreedomSpring/hello HTTP/1.1" 404 1012

어떤 아이디어?

해결법

  1. ==============================

    1.DispatcherServlet이 * .htm에 매핑됩니다.

    DispatcherServlet이 * .htm에 매핑됩니다.

    <servlet-mapping>
        <servlet-name>FreedomSpring</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    

    하지만 일치하지 않는 URL (http : // localhost : 8080 / FreedomSpring / hello)을 통해 컨트롤러에 액세스하고 있습니다. 세 가지 선택이 있습니다.

  2. from https://stackoverflow.com/questions/9260777/http-status-404-on-spring-3-1-mvc-app by cc-by-sa and MIT license