[SPRING] 스프링 부트가없는 스프링 데이터 JPA
SPRING스프링 부트가없는 스프링 데이터 JPA
스프링 부트는 Google App Engine에서 작동하지 않습니다 (적어도 나를위한 것은 아닙니다).
그러나 GitHub이나 다른 저장소에서 작성되었거나 사용 가능한 예제 중 많은 부분이 Spring Boot를 사용하고 있습니다. 이전처럼 스프링 부트를 사용하지 않고 일반 컨텍스트 XML을 사용하는 Spring-Data-JPA에 대한 예제가 있습니까?
그게 보여줄거야.
해결법
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==============================
1.이 예제를 작성했습니다.
이 예제를 작성했습니다.
src / main / webapp / WEB-INF / spring / context.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:jpa="http://www.springframework.org/schema/data/jpa" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa.xsd"> <context:property-placeholder location="/WEB-INF/spring/jdbc.properties" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.url}" p:username="${jdbc.username}" p:password="${jdbc.password}" /> <bean id="hibernateJpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" /> <!-- Configure the entity manager factory bean --> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter" ref="hibernateJpaVendorAdapter" /> <!-- Set JPA properties --> <property name="jpaProperties"> <props> <prop key="hibernate.dialect">${hibernate.dialect}</prop> </props> </property> <property name="packagesToScan" value="com.demo.data" /> </bean> <!-- Configure the transaction manager bean --> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <tx:annotation-driven /> <jpa:repositories base-package="com.demo.data" /> <context:component-scan base-package="com.demo.svc" /> </beans>
/src/main/webapp/WEB-INF/spring/jdbc.properties
# JDBC Connection jdbc.driverClassName=com.mysql.jdbc.Driver jdbc.url=jdbc:mysql://host:3306/db jdbc.username=user jdbc.password=password hibernate.dialect=org.hibernate.dialect.MySQLDialect
/src/main/webapp/WEB-INF/spring/servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd"> <context:component-scan base-package="com.demo.web" /> </beans:beans>
을 포함한다.
<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/context.xml</param-value> </context-param> <context-param> <param-name>webAppRootKey</param-name> <param-value>demo_jpa</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/servlet-context.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app>
Pom.hml
<properties> <org.springframework-version>4.1.7.RELEASE</org.springframework-version> <org.hibernate-em-version>4.3.8.Final</org.hibernate-em-version> <org.springframework.data-version>1.9.0.RELEASE</org.springframework.data-version> <dbcp-version>1.4</dbcp-version> <mysql-connector-version>5.1.28</mysql-connector-version> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> </properties> <dependencies> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-context-support</artifactId> <version>${org.springframework-version}</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-webmvc</artifactId> <version>${org.springframework-version}</version> </dependency> <dependency> <groupId>org.springframework.data</groupId> <artifactId>spring-data-jpa</artifactId> <version>${org.springframework.data-version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-entitymanager</artifactId> <version>${org.hibernate-em-version}</version> </dependency> <dependency> <groupId>mysql</groupId> <artifactId>mysql-connector-java</artifactId> <version>${mysql-connector-version}</version> </dependency> <dependency> <groupId>commons-dbcp</groupId> <artifactId>commons-dbcp</artifactId> <version>${dbcp-version}</version> </dependency> </dependencies>
데이터 엔티티 : com.demo.data.User
package com.demo.data; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name = "SYS_USERS") public class User { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "USER_ID") private int id; @Column(name = "USER_NAME") private String name; public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } }
Spring 데이터 JPA 저장소 : com.demo.data.UserRepository
package com.demo.data; import org.springframework.data.repository.CrudRepository; public interface UserRepository extends CrudRepository<User, Integer> { }
서비스
인터페이스 :
package com.demo.svc; import com.demo.data.User; public interface UserService { User findUserById(Integer id); }
이행:
package com.demo.svc; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Service; import com.demo.data.User; import com.demo.data.UserRepository; @Service public class UserServiceImpl implements UserService { @Autowired UserRepository userRepository; public User findUserById(Integer id) { return userRepository.findOne(id); } }
웹 컨트롤러 : com.demo.web.UserController
package com.demo.web; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.ResponseBody; import com.demo.svc.UserService; @Controller public class UserController { @Autowired UserService svc; @RequestMapping("/") @ResponseBody public String test() { return svc.findUserById(1).getName(); } }
from https://stackoverflow.com/questions/23974249/spring-data-jpa-without-spring-boot by cc-by-sa and MIT license
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